SOAP WSDL Generate Code

ManageServiceMetadataServiceSoap / Create

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Dim fso, outFile
Set fso = CreateObject("Scripting.FileSystemObject")
Set outFile = fso.CreateTextFile("output.txt", True)

set xml = CreateObject("Chilkat_9_5_0.Xml")
xml.Tag = "soapenv:Envelope"
success = xml.AddAttribute("xmlns:soapenv","http://schemas.xmlsoap.org/soap/envelope/")
success = xml.AddAttribute("xmlns","http://busdox.org/serviceMetadata/locator/1.0/")
success = xml.AddAttribute("xmlns:bus","http://busdox.org/serviceMetadata/ManageServiceMetadataService/1.0/")
xml.UpdateChildContent "soapenv:Header",""
xml.UpdateChildContent "soapenv:Body|CreateServiceMetadataPublisherService|PublisherEndpoint|LogicalAddress","https://example.com/"
xml.UpdateChildContent "soapenv:Body|CreateServiceMetadataPublisherService|PublisherEndpoint|PhysicalAddress","string"
xml.UpdateChildContent "soapenv:Body|CreateServiceMetadataPublisherService|ServiceMetadataPublisherID","string"

' In a SOAP HTTP request, including the XML declaration (<?xml version="1.0" encoding="UTF-8"?>) in the XML body is generally not required. 
xml.EmitXmlDecl = 0
soapRequestBody = xml.GetXml()

endpoint = "unknown"
soapAction = "http://busdox.org/serviceMetadata/ManageServiceMetadataService/1.0/:createIn"
'  For SOAP requests, the standard Content-Type is usually set to "text/xml" or "application/soap+xml"
contentType = "text/xml"

set http = CreateObject("Chilkat_9_5_0.Http")

http.ClearHeaders 
http.SetRequestHeader "Content-Type",contentType
http.SetRequestHeader "SOAPAction",soapAction

' resp is a Chilkat_9_5_0.HttpResponse
Set resp = http.PostXml(endpoint,soapRequestBody,"utf-8")
If (http.LastMethodSuccess = 0) Then
    outFile.WriteLine(http.LastErrorText)
    outFile.WriteLine("Failed to send SOAP request.")
    WScript.Quit
End If

' Get the XML response body.
set responseXml = CreateObject("Chilkat_9_5_0.Xml")
success = resp.GetBodyXml(responseXml)

statusCode = resp.StatusCode
outFile.WriteLine("response status code: " & statusCode)

' If the status code does not indicate succcess, then show the response XML,
' which probably contains error information.
If (statusCode <> 200) Then
    outFile.WriteLine(responseXml.GetXml())
    WScript.Quit
End If

outFile.WriteLine(responseXml.GetXml())

' Parse the successful SOAP response XML.

' This is a sample of the response XML, but the namespace prefixes will be different.
' We can parse the result using "*" for the namespace prefixes (see below).

outFile.Close
Request XML
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns="http://busdox.org/serviceMetadata/locator/1.0/" xmlns:bus="http://busdox.org/serviceMetadata/ManageServiceMetadataService/1.0/">
    <soapenv:Header/>
    <soapenv:Body>
        <CreateServiceMetadataPublisherService>
            <PublisherEndpoint>
                <LogicalAddress>https://example.com/</LogicalAddress>
                <PhysicalAddress>string</PhysicalAddress>
            </PublisherEndpoint>
            <ServiceMetadataPublisherID>string</ServiceMetadataPublisherID>
        </CreateServiceMetadataPublisherService>
    </soapenv:Body>
</soapenv:Envelope>
Response XML
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:bus="http://busdox.org/serviceMetadata/ManageServiceMetadataService/1.0/">
    <soapenv:Header/>
    <soapenv:Body>
        <bus:Create/>
    </soapenv:Body>
</soapenv:Envelope>