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<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
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<%
set xml = Server.CreateObject("Chilkat_9_5_0.Xml")
xml.Tag = "soap:Envelope"
success = xml.AddAttribute("xmlns:ubd","http://www.mf.gov.pl/uslugiBiznesowe/DI/UslugiUBD/2013/11/05")
success = xml.AddAttribute("xmlns:soap","http://www.w3.org/2003/05/soap-envelope")
success = xml.AddAttribute("xmlns:a05","http://www.mf.gov.pl/schematy/DI/UslugiUBD/2013/11/05")
xml.UpdateChildContent"soap:Header",""
xml.UpdateChildContent"soap:Body|a05:PobierzUpoPytanie|a05:NumerReferencyjny","string"
xml.UpdateChildContent"soap:Body|a05:PobierzUpoPytanie|a05:Jezyk","de"' In a SOAP HTTP request, including the XML declaration (<?xml version="1.0" encoding="UTF-8"?>) in the XML body is generally not required.
xml.EmitXmlDecl = 0
soapRequestBody = xml.GetXml()
endpoint = "https://test-ubd.mf.gov.pl/uslugi/dokumenty"
soapAction = "urn:PobierzUpo"' For SOAP requests, the standard Content-Type is usually set to "text/xml" or "application/soap+xml"
contentType = "text/xml"set http = Server.CreateObject("Chilkat_9_5_0.Http")
http.ClearHeaders
http.SetRequestHeader"Content-Type",contentType
http.SetRequestHeader"SOAPAction",soapAction
' resp is a Chilkat_9_5_0.HttpResponse
Set resp = http.PostXml(endpoint,soapRequestBody,"utf-8")
If (http.LastMethodSuccess = 0) ThenResponse.Write "<pre>" & Server.HTMLEncode( http.LastErrorText) & "</pre>"
Response.Write "<pre>" & Server.HTMLEncode("Failed to send SOAP request.") & "</pre>"
Response.EndEnd If' Get the XML response body.set responseXml = Server.CreateObject("Chilkat_9_5_0.Xml")
success = resp.GetBodyXml(responseXml)
statusCode = resp.StatusCodeResponse.Write "<pre>" & Server.HTMLEncode("response status code: " & statusCode) & "</pre>"
' If the status code does not indicate succcess, then show the response XML,
' which probably contains error information.If (statusCode <> 200) ThenResponse.Write "<pre>" & Server.HTMLEncode( responseXml.GetXml()) & "</pre>"
Response.EndEnd IfResponse.Write "<pre>" & Server.HTMLEncode( responseXml.GetXml()) & "</pre>"
' Parse the successful SOAP response XML.' This is a sample of the response XML, but the namespace prefixes will be different.
' We can parse the result using "*" for the namespace prefixes (see below).
Upo = responseXml.GetChildContent("*:Body|*:PobierzUpoOdpowiedz|*:Upo")
Status = responseXml.GetChildIntValue("*:Body|*:PobierzUpoOdpowiedz|*:Status")
StatusOpis = responseXml.GetChildContent("*:Body|*:PobierzUpoOdpowiedz|*:StatusOpis")
%>
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