SOAP WSDL Generate Code

BasicHttpBinding_MFET / NewSubmission

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Min Request Full Request 
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%
set xml = Server.CreateObject("Chilkat_9_5_0.Xml")
xml.Tag = "soapenv:Envelope"
success = xml.AddAttribute("xmlns:soapenv","http://schemas.xmlsoap.org/soap/envelope/")
success = xml.AddAttribute("xmlns:fas","http://www.fastenterprises.com")
xml.UpdateChildContent "soapenv:Header|fas:mvntHeader|fas:User","string"
xml.UpdateChildContent "soapenv:Header|fas:mvntHeader|fas:Password","string"
xml.UpdateChildContent "soapenv:Header|fas:mvntHeader|fas:Environment","P"
xml.UpdateChildContent "soapenv:Body|fas:SubmissionType","TC109XML"
xml.UpdateChildContent "soapenv:Body|fas:ReferenceId","string"
xml.UpdateChildContent "soapenv:Body|fas:File","BqozVXeZZg=="

' In a SOAP HTTP request, including the XML declaration (<?xml version="1.0" encoding="UTF-8"?>) in the XML body is generally not required. 
xml.EmitXmlDecl = 0
soapRequestBody = xml.GetXml()

endpoint = "https://tap.tax.utah.gov/efile/mfet/WSDL/"
soapAction = "http://www.fastenterprises.com/MFET/NewSubmission"
'  For SOAP requests, the standard Content-Type is usually set to "text/xml" or "application/soap+xml"
contentType = "text/xml"

set http = Server.CreateObject("Chilkat_9_5_0.Http")

http.ClearHeaders 
http.SetRequestHeader "Content-Type",contentType
http.SetRequestHeader "SOAPAction",soapAction

' resp is a Chilkat_9_5_0.HttpResponse
Set resp = http.PostXml(endpoint,soapRequestBody,"utf-8")
If (http.LastMethodSuccess = 0) Then
    Response.Write "<pre>" & Server.HTMLEncode( http.LastErrorText) & "</pre>"
    Response.Write "<pre>" & Server.HTMLEncode( "Failed to send SOAP request.") & "</pre>"
    Response.End
End If

' Get the XML response body.
set responseXml = Server.CreateObject("Chilkat_9_5_0.Xml")
success = resp.GetBodyXml(responseXml)

statusCode = resp.StatusCode
Response.Write "<pre>" & Server.HTMLEncode( "response status code: " & statusCode) & "</pre>"

' If the status code does not indicate succcess, then show the response XML,
' which probably contains error information.
If (statusCode <> 200) Then
    Response.Write "<pre>" & Server.HTMLEncode( responseXml.GetXml()) & "</pre>"
    Response.End
End If

Response.Write "<pre>" & Server.HTMLEncode( responseXml.GetXml()) & "</pre>"

' Parse the successful SOAP response XML.

' This is a sample of the response XML, but the namespace prefixes will be different.
' We can parse the result using "*" for the namespace prefixes (see below).

SubmissionId = responseXml.GetChildContent("*:Body|*:SubmissionId")

%>
</body>
</html>
Request XML
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:fas="http://www.fastenterprises.com">
    <soapenv:Header>
        <fas:mvntHeader>
            <fas:User>string</fas:User>
            <fas:Password>string</fas:Password>
            <fas:Environment>P</fas:Environment>
        </fas:mvntHeader>
    </soapenv:Header>
    <soapenv:Body>
        <fas:SubmissionType>TC109XML</fas:SubmissionType>
        <fas:ReferenceId>string</fas:ReferenceId>
        <fas:File>BqozVXeZZg==</fas:File>
    </soapenv:Body>
</soapenv:Envelope>
Response XML
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:fas="http://www.fastenterprises.com">
    <soapenv:Header/>
    <soapenv:Body>
        <fas:SubmissionId>string</fas:SubmissionId>
    </soapenv:Body>
</soapenv:Envelope>