Dim xml As NewChilkat.Xml
xml.Tag = "soapenv:Envelope"
xml.AddAttribute("xmlns:soapenv","http://schemas.xmlsoap.org/soap/envelope/")
xml.AddAttribute("xmlns:ser","urn:server")
xml.UpdateChildContent("soapenv:Header","")
xml.UpdateChildContentInt("soapenv:Body|ser:emitirDocumento|ser:documento|ser:opciones|ser:id_plantilla",1042)
xml.UpdateChildContentInt("soapenv:Body|ser:emitirDocumento|ser:documento|ser:opciones|ser:valores_brutos",1042)
xml.UpdateChildContent("soapenv:Body|ser:emitirDocumento|ser:documento|ser:opciones|ser:redondeo_tipo","string")
xml.UpdateChildContent("soapenv:Body|ser:emitirDocumento|ser:documento|ser:opciones|ser:empresa_email","string")
xml.UpdateChildContent("soapenv:Body|ser:emitirDocumento|ser:documento|ser:opciones|ser:empresa_web","string")
xml.UpdateChildContent("soapenv:Body|ser:emitirDocumento|ser:documento|ser:opciones|ser:retornar_sobredte","string")
' In a SOAP HTTP request, including the XML declaration (<?xml version="1.0" encoding="UTF-8"?>) in the XML body is generally not required.
xml.EmitXmlDecl = FalseDim soapRequestBody As String = xml.GetXml()
Dim endpoint As String = "https://conexion.facto.cl/documento.php"Dim soapAction As String = "https://conexion.facto.cl/documento.php/emitirDocumento"' For SOAP requests, the standard Content-Type is usually set to "text/xml" or "application/soap+xml"Dim contentType As String = "text/xml"Dim http As NewChilkat.Http
http.ClearHeaders()
http.SetRequestHeader("Content-Type",contentType)
http.SetRequestHeader("SOAPAction",soapAction)
Dim resp AsChilkat.HttpResponse = http.PostXml(endpoint,soapRequestBody,"utf-8")
If (http.LastMethodSuccess = False) Then
Debug.WriteLine(http.LastErrorText)
Debug.WriteLine("Failed to send SOAP request.")
Exit SubEnd If' Get the XML response body.Dim responseXml As NewChilkat.Xml
resp.GetBodyXml(responseXml)
Dim statusCode As Integer = resp.StatusCode
Debug.WriteLine("response status code: " & statusCode)
' If the status code does not indicate succcess, then show the response XML,
' which probably contains error information.If (statusCode <> 200) Then
Debug.WriteLine(responseXml.GetXml())
Exit SubEnd If
Debug.WriteLine(responseXml.GetXml())
' Parse the successful SOAP response XML.' This is a sample of the response XML, but the namespace prefixes will be different.
' We can parse the result using "*" for the namespace prefixes (see below).Dim status As Integer = responseXml.GetChildIntValue("*:Body|*:emitirDocumento|*:return|*:resultado|*:status")
Dim mensaje_error As String = responseXml.GetChildContent("*:Body|*:emitirDocumento|*:return|*:resultado|*:mensaje_error")