SOAP WSDL Generate Code

wiswebserviceSoap12 / LaborRatesByCityState

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Min Request Full Request 
Dim xml As New Chilkat.Xml
xml.Tag = "soap:Envelope"
xml.AddAttribute("xmlns:soap","http://www.w3.org/2003/05/soap-envelope")
xml.AddAttribute("xmlns:wis","http://www.wisinspections.com/")
xml.UpdateChildContent("soap:Header|wis:AuthenticateHeader|wis:Username","string")
xml.UpdateChildContent("soap:Header|wis:AuthenticateHeader|wis:Password","string")
xml.UpdateChildContent("soap:Body|wis:LaborRatesByCityState|wis:City","string")
xml.UpdateChildContent("soap:Body|wis:LaborRatesByCityState|wis:State","string")
xml.UpdateChildContent("soap:Body|wis:LaborRatesByCityState|wis:Term","string")


' In a SOAP HTTP request, including the XML declaration (<?xml version="1.0" encoding="UTF-8"?>) in the XML body is generally not required. 
xml.EmitXmlDecl = False
Dim soapRequestBody As String = xml.GetXml()

Dim endpoint As String = "http://www.wisinspections.com:8086/wiswebservice.asmx"
Dim soapAction As String = "http://www.wisinspections.com/LaborRatesByCityState"
'  For SOAP requests, the standard Content-Type is usually set to "text/xml" or "application/soap+xml"
Dim contentType As String = "text/xml"

Dim http As New Chilkat.Http

http.ClearHeaders()
http.SetRequestHeader("Content-Type",contentType)
http.SetRequestHeader("SOAPAction",soapAction)

Dim resp As Chilkat.HttpResponse = http.PostXml(endpoint,soapRequestBody,"utf-8")
If (http.LastMethodSuccess = False) Then
    Debug.WriteLine(http.LastErrorText)
    Debug.WriteLine("Failed to send SOAP request.")
    Exit Sub
End If


' Get the XML response body.
Dim responseXml As New Chilkat.Xml
resp.GetBodyXml(responseXml)

Dim statusCode As Integer = resp.StatusCode
Debug.WriteLine("response status code: " & statusCode)



' If the status code does not indicate succcess, then show the response XML,
' which probably contains error information.
If (statusCode <> 200) Then
    Debug.WriteLine(responseXml.GetXml())
    Exit Sub
End If


Debug.WriteLine(responseXml.GetXml())

' Parse the successful SOAP response XML.

' This is a sample of the response XML, but the namespace prefixes will be different.
' We can parse the result using "*" for the namespace prefixes (see below).


Dim LaborRatesByCityStateResult As String = responseXml.GetChildContent("*:Body|*:LaborRatesByCityStateResponse|*:LaborRatesByCityStateResult")
Request XML
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:wis="http://www.wisinspections.com/">
    <soap:Header>
        <wis:AuthenticateHeader>
            <wis:Username>string</wis:Username>
            <wis:Password>string</wis:Password>
        </wis:AuthenticateHeader>
    </soap:Header>
    <soap:Body>
        <wis:LaborRatesByCityState>
            <wis:City>string</wis:City>
            <wis:State>string</wis:State>
            <wis:Term>string</wis:Term>
        </wis:LaborRatesByCityState>
    </soap:Body>
</soap:Envelope>
Response XML
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:wis="http://www.wisinspections.com/">
    <soap:Header/>
    <soap:Body>
        <wis:LaborRatesByCityStateResponse>
            <wis:LaborRatesByCityStateResult>xml</wis:LaborRatesByCityStateResult>
        </wis:LaborRatesByCityStateResponse>
    </soap:Body>
</soap:Envelope>