SOAP WSDL Generate Code

SpringCMServiceSoap / DocumentCreateUploadChunk

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Min Request Full Request 
Dim xml As New ChilkatXml
xml.Tag = "soapenv:Envelope"
success = xml.AddAttribute("xmlns:soapenv","http://schemas.xmlsoap.org/soap/envelope/")
success = xml.AddAttribute("xmlns:spr","http://www.springcm.com/atlas/webservices/v201308/scm/")
xml.UpdateChildContent "soapenv:Header",""
xml.UpdateChildContent "soapenv:Body|spr:DocumentCreateUploadChunk|spr:token","string"
xml.UpdateChildContent "soapenv:Body|spr:DocumentCreateUploadChunk|spr:fileIdentifier","string"
xml.UpdateChildContentInt "soapenv:Body|spr:DocumentCreateUploadChunk|spr:index",1042
xml.UpdateChildContentInt "soapenv:Body|spr:DocumentCreateUploadChunk|spr:bufferLength",1042
xml.UpdateChildContent "soapenv:Body|spr:DocumentCreateUploadChunk|spr:buffer","BqozVXeZZg=="
xml.UpdateChildContent "soapenv:Body|spr:DocumentCreateUploadChunk|spr:md5Hash","BqozVXeZZg=="

' In a SOAP HTTP request, including the XML declaration (<?xml version="1.0" encoding="UTF-8"?>) in the XML body is generally not required. 
xml.EmitXmlDecl = 0
Dim soapRequestBody As String
soapRequestBody = xml.GetXml()

Dim endpoint As String
endpoint = "https://soapna11.springcm.com/atlas/webservices/v201308/springcmservice.asmx"
Dim soapAction As String
soapAction = "http://www.springcm.com/atlas/webservices/v201308/scm/DocumentCreateUploadChunk"
'  For SOAP requests, the standard Content-Type is usually set to "text/xml" or "application/soap+xml"
Dim contentType As String
contentType = "text/xml"

Dim http As New ChilkatHttp

http.ClearHeaders 
http.SetRequestHeader "Content-Type",contentType
http.SetRequestHeader "SOAPAction",soapAction

Dim resp As ChilkatHttpResponse
Set resp = http.PostXml(endpoint,soapRequestBody,"utf-8")
If (http.LastMethodSuccess = 0) Then
    Debug.Print http.LastErrorText
    Debug.Print "Failed to send SOAP request."
    Exit Sub
End If

' Get the XML response body.
Dim responseXml As New ChilkatXml
success = resp.GetBodyXml(responseXml)

Dim statusCode As Long
statusCode = resp.StatusCode
Debug.Print "response status code: " & statusCode

' If the status code does not indicate succcess, then show the response XML,
' which probably contains error information.
If (statusCode <> 200) Then
    Debug.Print responseXml.GetXml()
    Exit Sub
End If

Debug.Print responseXml.GetXml()

' Parse the successful SOAP response XML.

' This is a sample of the response XML, but the namespace prefixes will be different.
' We can parse the result using "*" for the namespace prefixes (see below).
Request XML
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:spr="http://www.springcm.com/atlas/webservices/v201308/scm/">
    <soapenv:Header/>
    <soapenv:Body>
        <spr:DocumentCreateUploadChunk>
            <spr:token>string</spr:token>
            <spr:fileIdentifier>string</spr:fileIdentifier>
            <spr:index>1042</spr:index>
            <spr:bufferLength>1042</spr:bufferLength>
            <spr:buffer>BqozVXeZZg==</spr:buffer>
            <spr:md5Hash>BqozVXeZZg==</spr:md5Hash>
        </spr:DocumentCreateUploadChunk>
    </soapenv:Body>
</soapenv:Envelope>
Response XML
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:spr="http://www.springcm.com/atlas/webservices/v201308/scm/">
    <soapenv:Header/>
    <soapenv:Body>
        <spr:DocumentCreateUploadChunkResponse/>
    </soapenv:Body>
</soapenv:Envelope>