SOAP WSDL Generate Code

OrganisationServiceWsHttpEndpoint / TransferDataManager

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Min Request Full Request 
Dim xml As New ChilkatXml
xml.Tag = "soap:Envelope"
success = xml.AddAttribute("xmlns:soap","http://www.w3.org/2003/05/soap-envelope")
success = xml.AddAttribute("xmlns:tra","http://training.gov.au/services/12/")
xml.UpdateChildContent "soap:Header",""
xml.UpdateChildContent "soap:Body|tra:TransferDataManager|tra:transferDataManagerRequest|tra:DataManagerCode","string"
xml.UpdateChildContent "soap:Body|tra:TransferDataManager|tra:transferDataManagerRequest|tra:EffectiveDate","date"
xml.UpdateChildContent "soap:Body|tra:TransferDataManager|tra:transferDataManagerRequest|tra:OrganisationCode","string"
xml.UpdateChildContent "soap:Body|tra:TransferDataManager|tra:transferDataManagerRequest|tra:RegistrationManagerCode","string"

' In a SOAP HTTP request, including the XML declaration (<?xml version="1.0" encoding="UTF-8"?>) in the XML body is generally not required. 
xml.EmitXmlDecl = 0
Dim soapRequestBody As String
soapRequestBody = xml.GetXml()

Dim endpoint As String
endpoint = "https://ws.staging.training.gov.au/Deewr.Tga.WebServices/OrganisationServiceV12.svc/Organisation12"
Dim soapAction As String
soapAction = "http://training.gov.au/services/12/IOrganisationService/TransferDataManager"
'  For SOAP requests, the standard Content-Type is usually set to "text/xml" or "application/soap+xml"
Dim contentType As String
contentType = "text/xml"

Dim http As New ChilkatHttp

http.ClearHeaders 
http.SetRequestHeader "Content-Type",contentType
http.SetRequestHeader "SOAPAction",soapAction

Dim resp As ChilkatHttpResponse
Set resp = http.PostXml(endpoint,soapRequestBody,"utf-8")
If (http.LastMethodSuccess = 0) Then
    Debug.Print http.LastErrorText
    Debug.Print "Failed to send SOAP request."
    Exit Sub
End If

' Get the XML response body.
Dim responseXml As New ChilkatXml
success = resp.GetBodyXml(responseXml)

Dim statusCode As Long
statusCode = resp.StatusCode
Debug.Print "response status code: " & statusCode

' If the status code does not indicate succcess, then show the response XML,
' which probably contains error information.
If (statusCode <> 200) Then
    Debug.Print responseXml.GetXml()
    Exit Sub
End If

Debug.Print responseXml.GetXml()

' Parse the successful SOAP response XML.

' This is a sample of the response XML, but the namespace prefixes will be different.
' We can parse the result using "*" for the namespace prefixes (see below).
Request XML
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:tra="http://training.gov.au/services/12/">
    <soap:Header/>
    <soap:Body>
        <tra:TransferDataManager>
            <tra:transferDataManagerRequest>
                <tra:DataManagerCode>string</tra:DataManagerCode>
                <tra:EffectiveDate>date</tra:EffectiveDate>
                <tra:OrganisationCode>string</tra:OrganisationCode>
                <tra:RegistrationManagerCode>string</tra:RegistrationManagerCode>
            </tra:transferDataManagerRequest>
        </tra:TransferDataManager>
    </soap:Body>
</soap:Envelope>
Response XML
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:tra="http://training.gov.au/services/12/">
    <soap:Header/>
    <soap:Body>
        <tra:TransferDataManagerResponse/>
    </soap:Body>
</soap:Envelope>